HYDRAULIC LOGGING WINCH

[Yoseph]

Hi, i am on project building a homemade hydraulic logging winch, using a Hamilton box reducer 1:37 and a 110A series Parker hydraulic motor, with hight torc and low speed. fixing all those parts on a frame. the oil supply will be a PVP33 Parker pump 33 cu inch displacement, the only things i have to do is building a frame to fix the pump on the rear frame of my IH B275 tractor i have to twist my pump to turn CW because if i face it to the pto its CCW rotation. i apologize for my poor english its not my usual language, will take pictures and show you my project.

 

[hr3]

welcome and I can't wait to see your pic's..

 

[Farmerford]

I am looking forward to seeing pictures too.

A question or two: if my mental math is right, at 540 rpm that pump will produce around 75 gallons per minute and if it is working at 2000 psi pressure will require about 85 horsepower to drive it. Does the IH B275 have that much horsepower?

Depending on length, etc., your pressure hoses will have to be 1 1/2 inches in diameter at least, and the suction line over 2 inches. Isn't that going to be awkward to work with?

Glad to have you as a member.

 

[oldnslo]

Yoseph,
The Parker PVP33 is 33 CC/rev which is 2 cubic inches displacement.

What is the RPM of your PTO? 540 or 1000?

At 540 RPM you will get 4.6 GPM

At 1000 RPM you will get 8.6 GPM

Will this pump operate properly at 540 RPM? Some pumps do not work very well below 600 RPM and other below 900 RPM.

Roy

 

[Yoseph]

It will operate at 1100 rpm, what i going to do to add 26 teeth to 13 teeth sprocket linked with Reynolds high strength chain, then my 540 output rpm will be 1080, witch is enough to operate my PVP33 at this speed the flow will be 10 gallon/min related to the manufacturer's data. the psi vs flow delivery is set by a built in gauge in the pump, one turn in /550psi. the flow can be set between 0 to the max at 17ｰ of the swash plate moving the plungers chamber.
my power take of is 33 HP or 25KW
thanks for your comments, will be glad to read you best knowledge and comments
will post pics as soon as possible

 

[Yoseph]

the frame is on the way, first fitting the axles, alignment, the jaw clutch must be smooth and easy to engage, the drum must be closest as possible at the center of the frame base, the next is welding the base, and fixing the parker motor to the gearbox the coupling is an elastic jaw.

 

[sizzami]

do you think it will be fast enough to skid logs?

 

[Yoseph]

Hi Sizzami
the speed depends on the flow pump output at 1500 psi and 14 GPM my motor runs at 447 RPM /37 after the worm gear 12.08 RPM*4inch drum diameter*3.14=152 inch/min about 13 feet/min
i think at this speed its enough for me, i could increase the speed by incresing the pump flow
thanks

 

[David Devuono]

I have looked at some of the worm drive gear boxes at my local Princess Auto. Even the large ones are only rated for 1-2 hp on the input. You will need to add a pressure gage, start out at a low pressure (500psi?) and see how it works. My concern is that you will blow that gearbox if your hydraulic motor puts out more then a couple of HP.

 

[Yoseph]

Hi David
I think your are right, now i am changing my plans to use roller chain sprockets reduction rather than my hamilton box, i will use two stage reduction 1:2.6 then 1:3.2 the output is 1 to 8.32, my pull power will be less than i expected, Thanks for the comments David

 

[Baby Grand]

Be sure to use real heavy chain & sprockets for that last stage ...

 

[Yoseph]

hi Baby Grand
thanks for your advise, what do you think about my roller chain its a RENOLD #60, the breaking strength is 7500lb, the servicing load is 2200lb, the shaft holding the sprockets 26 and 10 teeth for transmission between the drum(32 teeth) and hydraulic motor, is 1 inch diameter, i think i will reduce the length to the minimum as it will be the thickness of the two sprockets to increase the load on the shaft.
transmission is 10 to 26 and 10 to 32 the middle 26 an 10 are on the center shaft the ratio is 1 to 8.32
the output load will be 1500lb*8.32=11648lb/drum radius = 5200lbs decreasing on each layer, second layer 4778.6 lbs etc this is calculated by adding half diameter of the cable of each additional layer
thanks will be glad to read your advise

 

[955Lincoln]

Yoseph, are you still at 13 feet per minute with all of your changes? That seems slow for a logging winch. I'm going to be doing this same project sometime in the future and I have noticed logging winches, even the smaller models, run pretty fast compared to regular winches by watching some YouTube videos. I suppose if you will be pulling monster logs all of the time it would be ok but smaller ones may leave you tapping your foot.

 

[Baby Grand]

hi Baby Grand
thanks for your advise, what do you think about my roller chain its a RENOLD #60, the breaking strength is 7500lb, the servicing load is 2200lb, the shaft holding the sprockets 26 and 10 teeth for transmission between the drum(32 teeth) and hydraulic motor, is 1 inch diameter, i think i will reduce the length to the minimum as it will be the thickness of the two sprockets to increase the load on the shaft.
transmission is 10 to 26 and 10 to 32 the middle 26 an 10 are on the center shaft the ratio is 1 to 8.32
the output load will be 1500lb*8.32=11648lb/drum radius = 5200lbs decreasing on each layer, second layer 4778.6 lbs etc this is calculated by adding half diameter of the cable of each additional layer
thanks will be glad to read your advise

Yoseph-

Interesting project!
What will be the load in the chain that drives the spool of cable (last reduction stage) due to torque multiplication? From what you have here, I'm guessing it's 1500#*(26/10)= 3900#. That's almost twice your 2200# service load, which is why I'm thinking you may want a stronger chain for your final 10/32 stage.

There are 4 numbers I'd want to know:
1) Hyd motor max torque
2) Spool diameter
3) Cable diameter
4) Chain Pitch

-Jim

 

[davygp38]

Interesting project. what size cable are you planing on using? That spool looks like it will want a roller fair lead. Keep the pics coming.:thumbsup:

 

[Brad_Blazer]

It looks like you've got a good start on the winch. You can use double sprockets/chains on your final drive if a bigger chain is not an option.


If you decide to punt, check out this unit as an alternative starting point.
Surplus Center - 8000 LB PTO WINCH BASE MOUNT

 

[Baby Grand]

It looks like you've got a good start on the winch. You can use double sprockets/chains on your final drive if a bigger chain is not an option.


If you decide to punt, check out this unit as an alternative starting point.
Surplus Center - 8000 LB PTO WINCH BASE MOUNT

Brad,
I like that idea - keeps the chain, shafting & sprockets all the same series.

Yoseph,
Assuming 3400 in# max torque & .75 pitch chain:
First reduction is 1:2.6, so with torque multiplication = 8840 in# on the lay shaft. The 10 tooth sprocket has pitch diameter = 10*.75/Pi = 2.387in. Load in the second stage chain = 8840*2/2.387= 7406#.
I'm also thinking max line pull = 3400*8.32/2.25= 12,570#.

Do you have a pull cable clutch or quick load release of some sort figured into your design? With that kind of pull you could easily get yourself in a world of hurt and need a quick way to bail if everything starts to go south.

Somebody check my math - I gotta get to work.
-Jim

 

[jimgerken]

Surplus Center - 8000 LB PTO WINCH BASE MOUNT

I followed the above link to the Surplus Center page. If I do the math correctly, the speed the load would be dragged, with this winch, at full 540 PTO speed, is 20 feet per minute (single layer on the drum). Would someone please verify that I did that correctly?
Does this 20 feet per minute sound appropriate, or does it need to be faster? I'd rather not run the tractor at the full 540 all the time just to feel satisfied with the speed. I could put a chain speed increaser on the input to this winch, like speed it up about double, then run the tracot at half or 2/3 rpm. I have 35 pto hp. Thanks!!!!

 

[Baby Grand]

Surplus Center - 8000 LB PTO WINCH BASE MOUNT

I followed the above link to the Surplus Center page. If I do the math correctly, the speed the load would be dragged, with this winch, at full 540 PTO speed, is 20 feet per minute (single layer on the drum). Would someone please verify that I did that correctly?
Does this 20 feet per minute sound appropriate, or does it need to be faster? I'd rather not run the tractor at the full 540 all the time just to feel satisfied with the speed. I could put a chain speed increaser on the input to this winch, like speed it up about double, then run the tracot at half or 2/3 rpm. I have 35 pto hp. Thanks!!!!

20 ft/min does sound a bit like watching cabbage boil, especially with the engine thrumming away at PTO speed. That's 4 inces per second. I think the Farmi type winches can move along at 100 ft/min.

On the other hand, if the alternative is to carry the wood by hand or by wheelbarrow then it would be plenty fast for me.
-Jim

 

[Baby Grand]

29:1 gear ratio
540/29=18.62 Rev/min
D of first wrap = 4.125 + .375 = 4.5" (pitch diameter)
4.5*Pi*18.62*(1/12)=21.9 ft/min