rScotty
Super Member
- Joined
- Apr 21, 2001
- Messages
- 9,749
- Location
- Rural mountains - Colorado
- Tractor
- Kubota M59, JD530, JD310SG. Restoring Yanmar YM165D
HP = Torque X RPM / 5252. see link. The diagram above shows the F2803 engine making 155 ft-lb at 1650 rpm or about 49 hp, plenty for many jobs.
Yes, I'd say both are correct in their own context. You wrote your definition as a formula using mathematical notation. When using such formal notation it is quite correct to include constants.
My goal was a little different. I wanted to use a conversational format to show in an informal and non-mathematical way how even an obscure term like "torque RPM" can still contain the basic things we need to consider for calculating horsepower.
thank you,
rScotty