No, that's not right. Voltage and Amerage are proportional. If resistance is constant, then when voltage goes up or down the amperage follows. More voltage causes more amperage to flow, and vice versa.
And your sentence is not correct for Ohm's Law. Look it up anywhere. The sentence should say that if voltage decreases and resistance is constant, current decreases as well. Solve some examples and you can prove it to yourself. Ohm's law says amperage equals voltage divided by resistance.
I think the confusion comes about because a motor is not a very good example of pure resistace, and so using a motor makes it easy to confuse wattage with Ohm's law. Wattage is power, which is not the same as electrical resistance.
Wattage does equal voltage times amperage, so when power is held constant and you double the voltage then you can produce the same power at half the amperage. Hence the confusion.
What happens when you double the voltage to a motor with no load on it is that the coils will pull twice the amperage and the added force will try to run the motor at twice the speed. In a perfect frictionless vacuum that is what would happen for as long as the coils can handle the heat.
But if you put a load on a motor and only let that motor rev up to meet the load, then you are right that doubling the voltage will create the same power at a lower amperage.
In a glow plug there is no limit to the load, so decreasing the voltage will simply decrease the voltage and the glow plug will not get very hot.
Hope this helps,
rScotty