I have a 55.3 Horsepower Engine and I have a 35400lbs load.
I will have to choose the pump , gearbox and drum. Can you help me?
It takes 53 HP to pump 26 GPM at 3000 psi, so if you run that engine at 2500 rpm. you will need a pump with 2.4 cu in.
You need to figure the gear box, to pull that load.
A hydraulic motor of 2.4 cu in, at 3000 psi, will have 1,146 in lbs.of torque , 2403 rpm motor speed at 100 %
26gpm and 3000 psi is not 53hp. it's 44.5 ?
can you give me a hand in the easy part. how did you get the displacement and the rpm?
(26 x 3000) / 1714= 45
Don't forgot about efficiency. I think it has been said here that the pump efficiency is ~80%.
Chris
It appears that your formula is using an efficiency of 85 % according to the people that wrote the formula from the hydraulic site. So if that is true, then you lose some HP in the transfer of power. That means that you have 45 HP going to the pump using a 53 HP engine.
I believe this is correct, but if not, someone will correct it.
How about telling us what it is you are trying to pull, and is it a rolling load or a static load. or is this just a test question.
You do know, that with the proper gear ratio, you can just about move anything. IE, torque multiplier.