Turbo,
That decimal factor you used is NOT for rod diameter, but rather metal thickness of the part you are going to weld with, and even that is not entirely right. And with that, you have to select the right rod diameter with the correct RANGE of amps No way 93 amps is suitable for a 3/32 rod, especially a 60XX series.
No, I am correct, this is an acceptable guideline to use as a
starting point for a given rod size. He has 3/32" on hand so that is what I used for my example. I would not use a 3/32' electrode on 12 gage but that is what the OP has and he question was what was the proper amperage for the rod not the material thickness.
I was trying to keep it simple, if you want to full version I can give that to you. The proper procedure is too determine the proper amperage and rod size based on material thickness, joint design and position of weld.
I pulled out my "ASM Metals Hand Book on Welding and Brazing" as well as my "Lincoln Procedure Handbook Of Arc Welding" to get the values below
These recommend ranges are for DC straight polarity current - AC requires approximately 10% higher current due to th
I could muddy it up and throw in the DC reverse current requirements but since he has an AC welder I won't.
I will use 1/8" diameter as an example
6011 100 -120 amps (AC 110-130 etc. etc.)
6013 120- 140 amps
7018 120 -140 amps
7104 140 -160 amps ( higher amps needed due to the iron powder in the coating)
7024 160 -170 amps (has a higher % iron then 7014)
Again, this is a
starting point - your mileage will vary by many things including the type of welder your are using.
I always found that the DC motor driven welders (and the new solid state welders) seemed to need create more "heat" then the AC buzz box.