BB_TX
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- Joined
- Jan 29, 2002
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- JD 950
Chris-I have been looking to do the same thing with a 30' span over a creek. I found a book on structural design that gives some tables to do some calculations. The basic formula is W=(1795*A*D)/L where W is the greatest safe load in pounds in the middle of an I beam, A is the cross sectional area of the I beam in sq. in., D is the depth of the I beam in inches, L is the length of the beam in feet. Here are some typical I beam numbers;
8" I beam (18.4 lb/ft) A = 5.34
10" I beam (25.4 lb/ft) A = 7.38
12" I beam (31.8 lb/ft) A = 9.26
(these are the lightest weight beams for each height. you can get heavier beams with greater A)
If you run the numbers for a length of 16', then you see the greatest safe load in the center for;
8" = 4792 lbs
10" = 8279 lbs
12" = 12466 lbs
That load would be any materials that went into building the bridge plus any weight you put on the bridge.
I am not a structural engineer so I am not sure what all else should be considered. But it is a starting point. I am still working on it.
8" I beam (18.4 lb/ft) A = 5.34
10" I beam (25.4 lb/ft) A = 7.38
12" I beam (31.8 lb/ft) A = 9.26
(these are the lightest weight beams for each height. you can get heavier beams with greater A)
If you run the numbers for a length of 16', then you see the greatest safe load in the center for;
8" = 4792 lbs
10" = 8279 lbs
12" = 12466 lbs
That load would be any materials that went into building the bridge plus any weight you put on the bridge.
I am not a structural engineer so I am not sure what all else should be considered. But it is a starting point. I am still working on it.