Need help figuring out what this motor is......

[Brad_Blazer]

You could run it from a dedicated pump at lower pressure to get the speed you want and transmit all of the power you have available.

 

[mx842]

You could run it from a dedicated pump at lower pressure to get the speed you want and transmit all of the power you have available.

I'm not sure I follow you. But running more than one pump on this processor is not something I really wanted to do. If I have to wait until I come across a larger engine then I'll just have to wait for awhile longer. I'm still looking for a pump and a valve to run this thing and just wanted to weed out stuff that is to small for the job. I was thinking about running part of the unit, log clamp, splitter, wedge adjustor and possibly the saw blade cylinder from a three or four lever hydraulic valve and the saw motor, out feed conveyor motor, and probably the live deck by electric solenoid valves.

I've been trying to figure out how to incorporate the log clamp, saw motor, and blade control cylinder sequenced together all by one electric control but I'm still having trouble getting my brain to filter all that out.

If I have to run more than one pump I guess that wouldn't be to hard to configure into the system but I still don't get why I would need to do so. The saw motor will only be pulling power a small part of the time much like the majority of the different parts of the unit. Hopefully you can elaborate a little more on this point of thought. Thanks for your reply.

 

[J_J]

What I think he alluding to is that if you try and run everything off of one pump, each item you activate will take a certain amount of fluid.

If you want a constant flow, you will have to use a priority divider circuit, or several pumps.

If you are try to do multiple things at once, your timing may be off on critical things.

An engine can drive multiple pumps, like one feeding the saw motor, and the other the splitter, log lift, conveyor, etc.

GPM's determines the speed of operation, so if one component takes half of the fluid, the other component will slow down, etc.

You probably want max speed on the splitter cyl and the saw.

 

[mx842]

What I think he alluding to is that if you try and run everything off of one pump, each item you activate will take a certain amount of fluid.

If you want a constant flow, you will have to use a priority divider circuit, or several pumps.

If you are try to do multiple things at once, your timing may be off on critical things.

An engine can drive multiple pumps, like one feeding the saw motor, and the other the splitter, log lift, conveyor, etc.

GPM's determines the speed of operation, so if one component takes half of the fluid, the other component will slow down, etc.

You probably want max speed on the splitter cyl and the saw.

Thanks JJ, I was thinking that is what he meant but just wasn't sure. What is the best way to run multiple pumps off a single engine? I would assume you would have to run them off belts and pulleys??

 

[J_J]

No, some of the grounds keepers machine, use three or four pumps piggybacked on a single shaft.

Surplus Center

A pumps flow and pressure will dictate the HP required to drive it to full capacity.

 

[mx842]

No, some of the grounds keepers machine, use three or four pumps piggybacked on a single shaft.

Surplus Center

A pumps flow and pressure will dictate the HP required to drive it to full capacity.

Silly me, I had been looking at multiple pumps and motors for days while searching for info on this big motor I have. It just never registered what I was looking at when I was looking at them.:duh:

I get cornfused when I start looking at the graphs and charts about input/output/gpm's@ this or that RPM of a pump as it equates to what the effects are on a motor, pressure??? gpm..... torque, speed it will turn a load. I guess the question I need to ask is if I have a 62.7 hydraulic motor designed to run @ 2000 rpm's what size pump will I need to hook up to it to get the full RPM potential and how do I turn those 2000 RPM's into the 5500 to 6000 feet per minute or what ever it is, needed to drive that 3/4 drive chain. Is there a chart somewhere to figure all that out?

 

[J_J]

62.7 cu in is a rather large motor, and if you gave it 20 GPM, it would run at 74 rpm.

A 10 to 1 ratio would turn a shaft at 740 rpm.

To get 2000 rpm out of a motor that large, you would need about 550 GPM's.

The motor will run given about any GPM.

Motor torque would be about 24,881 in lbs, at 2500 psi.

I could visualize you using about 20 GPM for the log splitter.

------------------------------------5---------------hyd chain saw.

------------------------------------3---------------log lift.

------------------------------------3---------------log pusher.

------------------------------------3---------------for conveyer.

Maybe more, maybe less if using a pump for multiple things.

A pump or pumps needed to produce 34 GPM's using engine speed of 3600 rpm would have a displacement of 2.2 cu in.

HP required would be about 58.

If you need some help , go to the technical help here. Surplus Center

Use the hyd calculators in the left panel.

Surplus Center

 

[J_J]

This 2.31 cu in pump will produce about 34 GPM's at 3600 rpm and has a psi rating of 3000.

2.31 cu in PRINCE HYD PUMP SP25A38A9H2R

You would have to divide the output for different operations.

A tandem pump would be preferred for different flow rates.