Hydraulic help

   / Hydraulic help #1  

nyen0004

Silver Member
Joined
Jan 27, 2011
Messages
119
Location
Morewood, Ontario, Canada
Tractor
John Deere 2320
Hey everyone I am planning on building a dump cart for my JD2320. I want to make it hydraulic dump, and not knowing anything to do with hydraulics I would like you guys help to figure out what size of cylinder to use. I thinking on a 4 x 6 trailer. Any info would be great. Thanks
 
   / Hydraulic help #2  
There are too many variables to just say this size will work.

Will it be a scissors lift or straight lift?

What pressure will it operate at?

What distance from pivot point?

etc..
 
   / Hydraulic help
  • Thread Starter
#3  
I am thinking just a straight lift, The spec for my tractor say the hydraulics run at 2400psi. AS for pivot point I dont know that is why I'm asking everyone. I there some kind of formula to figure pivot point/cylinder size/etc?
 
   / Hydraulic help #4  
Straight lift requires less figuring. For cylinders force = area time pressure.

example: 4 " bore cylinder has 12.5 square in area times 1000 PSI = 12,566 lbs of force or at 2000 PSI you have 25,133 lbs of force. Figure a yard of wet dirt is 2500 - 3000 lbs you can in theory lift 8 + yards. If your pivot point is at the opposite end of a 6 foot trailer with the load even distributed you could in theory haul 16 + yards.

Never use max system pressure to figure cylinder forces unless you are using a single acting cylinder or moving very slowly. There will ALWAYS be line losses on tractors. Generic rule of thumb I use 85 - 90 % of max pressure should give you a close estimate on the actual force you will be able to achieve while the cylinder is moving at a reasonable speed.
 

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