The lever to which the force is applied is 10 feet long - from the pivot point of the boom at the top link connection on the tractor. The distance from the top link connection to the pivot point on the PHD gear box is 5 feet and even though the boom is longer and curved this straight line distance is the lever. Since the whole assembly is rigidly connected together it acts as though the PHD gear box is attached in the middle of the 10 foot lever to which the force is applied. Thus the lever is a simple second class lever as you indicated with the load in the middle and the force applied to the load is 2x the force applied to the lever. The assumption is made that the tractor is a fixed object in this problem. This is a good assumption in this case since the tractor is much heavier (5X) than the other forces being considered in the problem. You could look at the problem as a class 1 lever with the pivot point of the PHD being the fulcrum and the force being applied to the end of the lever to lift the tractor; however, it would not be an interesting problem since something would break before enough force could be applied to lift this tractor. If the tractor were smaller then it would be something to look at to determine the limit of the force that could be applied and/or how long the lever could be made before the tractor lifted. I am or rather was an engineer and although I was an electrical engineer they made us study engineering mechanics as part of the EE program at UT. This is a simple mechanics problem once you simplify the force diagram.