tmeric7
Bronze Member
- Joined
- May 2, 2020
- Messages
- 61
- Tractor
- New Holland TC29DA, Allis Chalmers B, Cub Cadet 102
Yes, I agree on everything.Tmeric7 please correct me if I’m wrong. Elementally little difference between HR or CR steel. CR has twice the yield strength due to the shaping process. Higher dimensional tolerance and better surface finish. Also cost about double.
Take piece of CR and stick it in a forge, heat to bend or weld it anneals back to HR strength in the heated areas. Mechanical fasteners preferred attachment to maintain strength.
General rule of thumb. Exceptions because there are so many alloys. Many considerations when designing equipment and fixtures.
Worked with making and cold forming cermets. Quickly cold work harden thru a rolling mill.
CR and HR are forming processes independent of elemental composition. You can do either to many alloys. 1020 is 99.8% iron and 0.2% carbon, by weight, no matter how you form it. Although, the way you form in can change the properties.
In class we describe annealing as a "reset" button to go back to the initial properties before cold working. (Hot working does not change properties.) There are different forms or annealing, but all reasonably similar. This is done "around" 700C for various alloys. Got to hold it there a little while for the atoms to find their home again.
This all works because of small imperfection in the atomic lattice. Imagine all these iron atoms arranged in rows and columns with a few carbon atoms sprinkled in. It's mostly orderly, buy there are small imperfections here and there. Imperfections called "dislocation" allow atoms to move around under high load and this is why metals bend without breaking, but you only get so much. Eventually the dislocations get hung up on each other or run into grain boundaries. That's why the yield strength goes up... it gets to where you need more force to move the atoms around. But because the atoms cant move, you can't deform much more (more brittle). Annealing, with expansion of material, allows the atoms to move around and get past the "hang-ups" and back to a pre-deformed state.
For what it's worth, I expect that any common alloy would have worked for the OP's original question, given enough thickness in the material. This would be a good one for the students to solve out!