2006, JD 2305, 1.5 amp diode receptacle replacement

[William Reed]

This is the 4th time I'm replacing the 4 way flasher, 1.5 amp diode. Unfortunately this time I can't get the diode out. Looking for a replacement receptacle. JD doesn't sell them and wondered if anyone has replaced one on their 2210 or 2305? Looked on line with zero results. Also going to replace the light switch as I feel it's causing the diode to fail and occasionally the 4 way flashers can't be turned off. Thank you.

 

[Dave M7040]

This is the 4th time I'm replacing the 4 way flasher, 1.5 amp diode. Unfortunately this time I can't get the diode out. Looking for a replacement receptacle. JD doesn't sell them and wondered if anyone has replaced one on their 2210 or 2305? Looked on line with zero results. Also going to replace the light switch as I feel it's causing the diode to fail and occasionally the 4 way flashers can't be turned off. Thank you.

Let me start by saying I am, not a JD expert.

Over many years, from looking at their electrical schematics and WSM for models like the 2210, my impression is that the various diodes are part of the safety circuit designed to protect expensive components from reversed battery jumper cables or reversed battery charger cables

Safety Circuit:
A safety circuit consisting of the K3 safety relay 1, and the V6 diode is installed in the circuit
to protect the N1 voltage regulator/rectifier from reverse battery polarity.
When the battery is correctly charged and connected, and the key switch is in the RUN position,
battery current flows from positive terminal to the starting motor terminal, 200 and 201 Wht, F1
fuse, 202 Wht, 205 Wht/Red wire, S1 key switch, 405 and 407 Red, F2 fuse, 421 and 425 Red wires to
the K4 safety relay 1 contact.
Battery current also flows through the 421 and 426 Red wire, V6 diode, and 465 and 466 Lt Grn wires
to the K3 Safety Relay 1 coil.
The relay coil is energized, the contacts close and current is provided to the N1 voltage
regulator/rectifier through the contacts and 467 Red/Blu wire.
If the battery is connected in reverse (positive to ground and negative to power circuits) or the
battery was charged in reverse, positive voltage is provided to both sides of the safety relay coil
(100 and 126 Blk wires to one side; and 100, 125 Blk wires, V8 diode, and 464 Lt Grn wire to the
other side).
With no voltage difference across the coil, the coil is not energized and the relay contacts do not
close.
If the contacts did close with the battery connected in reverse or the battery charged in reverse,
a ground path would be established through the 425, 421 Red wire, F2 fuse, 407 Red, S1 key switch,
205 Wht/Red wire, 202 Wht, F1 fuse, 201/200 Wht and starting motor terminal to the battery.
Reversed sensing current would be provided to the voltage regulator/rectifier thru the 203 and 210
Wht and damage to it would occur.
NOTE: Diodes usually fail “open”, but can fail “shorted”. If any problem occurs with the charging
system, check both V6 and V8 diodes.

Do you have the WSM and if so can you specify which diode is continually failing?

Dave M7040

 

[William Reed]

I have the wiring schematic and believe it's the V6 diode although in a post on how to change the diode, it's identified by that person as the V7 diode. Either way, I broke the diode receptacle and is not available from JD so I'll have to wire the replacement in using stakons. Also believe the diode problem may be due to a faulty turn signal switch that won't allow me to shut off the flashers no matter what position it's in. Currently have no flashers or turn signals. Last check the fuse was good.

 

[WranglerX]

Try a electronics supply instead of JD parts.... Might also try a diode with higher rating, if 1.5 amp diode keeps failing, then the current load on diode is more than diode rating, try something like 3 amp diode also be aware of voltage rating of diode ...

https://www.digikey.com/

https://www.alliedelec.com/

Dale

 

[William Reed]

Thank you